How to get second last field from a cut command
Got a hint from Unix cut except last two tokens and able to figure out the answer :
cat datafile | rev | cut -d '/' -f 2 | rev
There's no need to use cut, rev, or any other tools external to bash here at all. Just read each line into an array, and pick out the piece you want:
while IFS=, read -r -a entries; do printf '%s\n' "${entries[${#entries[@]} - 2]}"done <fileDoing this in pure bash is far faster than starting up a pipeline, at least for reasonably small inputs. For large inputs, the better tool is awk.