How to pass arguments to /bin/bash? [closed]
Drop the -c altogether. From the manpage:
bash [options] [file]…Bash is an sh-compatible command language interpreter that executes commands read from the standard input or from a file.Thus, you can execute your program via
bash myprogram myfile.extand myfile.ext will be the first positional parameter.
bash -l myprogram myfile.extwill work as well, (but whether or not bash is invoked as a login shell seems tangential to this question.)
-c string If the -c option is present, then commands are read from string. If there are arguments after the string, they are assigned to the positional parameters, starting with $0.You need to quote the command passed in as string so it's treated as a single argument for the -c option, which then gets executed normally with the argument following the command, i.e.
/bin/bash -c -l 'myprogram myfile.ext'