How to remove leading whitespace from each line in a file

sed "s/^[ \t]*//" -i youfile

Warning: this will overwrite the original file.

For this specific problem, something like this would work:

$ sed 's/^ *//g' < input.txt > output.txt

It says to replace all spaces at the start of a line with nothing. If you also want to remove tabs, change it to this:

$ sed 's/^[ \t]+//g' < input.txt > output.txt

The leading "s" before the / means "substitute". The /'s are the delimiters for the patterns. The data between the first two /'s are the pattern to match, and the data between the second and third / is the data to replace it with. In this case you're replacing it with nothing. The "g" after the final slash means to do it "globally", ie: over the entire file rather than on only the first match it finds.

Finally, instead of < input.txt > output.txt you can use the -i option which means to edit the file "in place". Meaning, you don't need to create a second file to contain your result. If you use this option you will lose your original file.

You can use AWK:

$ awk '{$1=$1}1' filefor (i = 0; i < 100; i++)for (i = 0; i < 100; i++)for (i = 0; i < 100; i++)for (i = 0; i < 100; i++)for (i = 0; i < 100; i++)for (i = 0; i < 100; i++)for (i = 0; i < 100; i++)

sed

$ sed 's|^[[:blank:]]*||g' filefor (i = 0; i < 100; i++)for (i = 0; i < 100; i++)for (i = 0; i < 100; i++)for (i = 0; i < 100; i++)for (i = 0; i < 100; i++)for (i = 0; i < 100; i++)for (i = 0; i < 100; i++)

The shell's while/read loop

while read -r linedo    echo $linedone <"file"