How to select lines between two marker patterns which may occur multiple times with awk/sed

Use awk with a flag to trigger the print when necessary:

$ awk '/abc/{flag=1;next}/mno/{flag=0}flag' filedef1ghi1jkl1def2ghi2jkl2

How does this work?

• /abc/ matches lines having this text, as well as /mno/ does.
• /abc/{flag=1;next} sets the flag when the text abc is found. Then, it skips the line.
• /mno/{flag=0} unsets the flag when the text mno is found.
• The final flag is a pattern with the default action, which is to print $0: if flag is equal 1 the line is printed.

For a more detailed description and examples, together with cases when the patterns are either shown or not, see How to select lines between two patterns?.

Using sed:

sed -n -e '/^abc$/,/^mno$/{ /^abc$/d; /^mno$/d; p; }'

The -n option means do not print by default.

The pattern looks for lines containing just abc to just mno, and then executes the actions in the { ... }. The first action deletes the abc line; the second the mno line; and the p prints the remaining lines. You can relax the regexes as required. Any lines outside the range of abc..mno are simply not printed.

This might work for you (GNU sed):

sed '/^abc$/,/^mno$/{//!b};d' file

Delete all lines except for those between lines starting abc and mno