Making new files automatically executable?

umask for files is subtracted from 666 and for directories it is subtracted from 777. So if your umask is 002 and you create a directory, you get 775 (777 - 002), and if you create a file you get 664 (666 - 002).

The umask merely subtracts default file and directory permissions.

777 initial file permissions111 execute bit is not set by default---666 default file permissions022 subtract default Unix umask---644 voila, final file permissions

The execute bit must be set for the owner to cd into a directory of their creation, so user-execute permission is set, resulting in directory permissions of 744, when using the above umask.

I have found no way to setting which would set the execute, by default. This would be bad mojo, anyway, but I am currently researching for a cyber security course I am writing.

In a safe way? No.In an unsafe manner: just change the umask by adding umask xxx in your ~/.bashrc file, where xxx represents the permission mask you wish.

Notes:

1. This is unsafe (did I already mention it? Other did.)
2. It may leads to many issues. One being the creation of filesdisallowed on some systems)

Recommended way:

Only do it for files that actually need the execute permission.

chmod +x /the/file