UNIX Programming. struct timeval how to print it (C-programming)

In the GNU C Library, struct timeval:

is declared in sys/time.h and has the following members:

long int tv_sec

This represents the number of whole seconds of elapsed time.

long int tv_usec

This is the rest of the elapsed time (a fraction of a second), represented as the number of microseconds. It is always less than one million.

So you will need to do

printf("%ld.%06ld\n", usage.ru_stime.tv_sec, usage.ru_stime.tv_usec);

to get a "nicely formatted" timestamp like 1.000123.

Since struct timeval will be declared something like:

struct timeval {    time_t      tv_sec;    suseconds_t tv_usec;}

you need to get at the underlying fields:

printf ("%ld.%06ld\n", usage.ru_stime.tv_sec, usage.ru_stime.tv_usec);printf ("%ld.%06ld\n", usage.ru_utime.tv_sec, usage.ru_utime.tv_usec);

yeah its

int main( void ){    clock_t start, stop;    long int x;    double duration;    static struct timeval prev;    struct timeval now;    start = clock();  // get number of ticks before loop    for( x = 0; x < 1000000000; x++ );    // sleep(100);    stop = clock();  // get number of ticks after loop    // calculate time taken for loop    duration = ( double ) ( stop - start ) / CLOCKS_PER_SEC;    printf( "\nThe number of seconds for loop to run was %.2lf\n", duration );    gettimeofday(&now, NULL);    prev.tv_sec = duration;    if (prev.tv_sec)    {        int diff = (now.tv_sec-prev.tv_sec)*1000+(now.tv_usec-prev.tv_usec)/1000;        printf("DIFF %d\n",diff);    }    return 0;}