Any way to exit outer function from within inner function?
<?php function funcA() { try { funcB(); echo 'Hello, we finished funcB'; } catch (Exception $e) { //Do something if funcB causes an error, or just swallow the exception } } function funcB() { echo 'This is funcB'; //if you want to leave funcB and stop funcA doing anything else, just //do something like: throw new Exception('Bang!'); }?>
The only way I see is using exceptions:
function funcA() { funcB(); echo 'Hello, we finished funcB';}function funcB() { throw new Exception; echo 'This is funcB';}?><p>This is some text. After this text, I'm going to call funcA.</p><p><?php try { funcA(); } catch (Exception $e) {} ?></p><p>This is more text after funcA ran.</p>Ugly, but it works in PHP5.