Changing the start up location of a WPF window
Just set WindowStartupLocation, Height, Width, Left, and Top in xaml:
<Window x:Class="WpfApplication1.Window1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="Window1" Height="500" Width="500" WindowStartupLocation="Manual" Left="0" Top="0"></Window>
For people who like me wanted to set the position of the window to the current mouse position, you can do it like this:
myWindow.WindowStartupLocation = WindowStartupLocation.Manual;myWindow.Left = PointToScreen(Mouse.GetPosition(null)).X;myWindow.Top = PointToScreen(Mouse.GetPosition(null)).Y;
I like to use WindowStartupLocation="CenterOwner" (MSDN docs for it)
The caller needs to specify itself as owner for this to work though, such as:
new MyWindow() { Owner = this }.ShowDialog();Then just define the window height and width, e.g:
<Window ... Height="400" Width="600" WindowStartupLocation="CenterOwner">...