Get owner of context menu in code

this will give you the exact thing you want

private void OnDeleteClicked(object sender, System.Windows.RoutedEventArgs e){    MenuItem mnu = sender as MenuItem;    StackPanel sp = null;    if(mnu!=null)    {        sp = ((ContextMenu)mnu.Parent).PlacementTarget as StackPanel;    }}

Hope this helps!!

The visual tree for ContextMenus and Popups works a little differently. You can use ContextMenu.PlacementTarget to get the StackPanel. There is more information available on MSDN here: http://msdn.microsoft.com/en-us/library/system.windows.controls.contextmenu.placementtarget.aspx

the context menu has its own visual tree, try this calling this from your event handler like so :-

StackPanel stackPanel = GetStackPanelItemFromContextMenu((FrameworkElement)sender, yourStackPanel);  private StackPanel GetStackPanelItemFromContextMenu(FrameworkElement sender, StackPanel stackPanel) {     Point menuClickPoint = ((sender as FrameworkElement).Parent as ContextMenu).TranslatePoint(new Point(0, 0), stackPanel);     // get the first potential object that was hit        DependencyObject obj = stackPanel.InputHitTest(menuClickPoint) as DependencyObject;     // cycle up the tree until you hit the StackPanel     while (obj != null && !(obj is StackPanel)) {        obj = VisualTreeHelper.GetParent(obj);     }     return obj as StackPanel;  }