touchIDLockout deprecated in iOS 11.0
Short answer: It looks like a compiler bug to me, causedby the import of a C enumeration which defines multiple constantswith the same value.
Long answer: Unfortunately I do not have a solution how to avoid the deprecationwarning, only a possible explanation what causes it.
The LAError
codes are defined as a C enumeration in <LAError.h>
in the LocalAuthentication framework. Here is anextract of that definition:
// Error codes#define kLAErrorAuthenticationFailed -1#define kLAErrorUserCancel -2// ...#define kLAErrorTouchIDNotAvailable -6#define kLAErrorTouchIDNotEnrolled -7#define kLAErrorTouchIDLockout -8// ...#define kLAErrorBiometryNotAvailable kLAErrorTouchIDNotAvailable#define kLAErrorBiometryNotEnrolled kLAErrorTouchIDNotEnrolled#define kLAErrorBiometryLockout kLAErrorTouchIDLockouttypedef NS_ENUM(NSInteger, LAError){ LAErrorAuthenticationFailed = kLAErrorAuthenticationFailed, LAErrorUserCancel = kLAErrorUserCancel, // ... LAErrorTouchIDNotAvailable NS_ENUM_DEPRECATED(10_10, 10_13, 8_0, 11_0, "use LAErrorBiometryNotAvailable") = kLAErrorTouchIDNotAvailable, LAErrorTouchIDNotEnrolled NS_ENUM_DEPRECATED(10_10, 10_13, 8_0, 11_0, "use LAErrorBiometryNotEnrolled") = kLAErrorTouchIDNotEnrolled, LAErrorTouchIDLockout NS_ENUM_DEPRECATED(10_11, 10_13, 9_0, 11_0, "use LAErrorBiometryLockout") __WATCHOS_DEPRECATED(3.0, 4.0, "use LAErrorBiometryLockout") __TVOS_DEPRECATED(10.0, 11.0, "use LAErrorBiometryLockout") = kLAErrorTouchIDLockout, // ... LAErrorBiometryNotAvailable NS_ENUM_AVAILABLE(10_13, 11_0) __WATCHOS_AVAILABLE(4.0) __TVOS_AVAILABLE(11.0) = kLAErrorBiometryNotAvailable, LAErrorBiometryNotEnrolled NS_ENUM_AVAILABLE(10_13, 11_0) __WATCHOS_AVAILABLE(4.0) __TVOS_AVAILABLE(11.0) = kLAErrorBiometryNotEnrolled, LAErrorBiometryLockout NS_ENUM_AVAILABLE(10_13, 11_0) __WATCHOS_AVAILABLE(4.0) __TVOS_AVAILABLE(11.0) = kLAErrorBiometryLockout, // ...} NS_ENUM_AVAILABLE(10_10, 8_0) __WATCHOS_AVAILABLE(3.0) __TVOS_AVAILABLE(10.0);
One can see that "old" (deprecated) and the "new" error codes usethe same values. For example, both LAErrorTouchIDNotAvailable
and LAErrorBiometryNotAvailable
are defined as -6
.
That is perfectly valid in C, but the raw values of a Swift enum
mustbe mutually distinct. Apparently the Swift importer solves that bymapping the new/duplicate cases to static variables.
Here is an extract of the Swift mapping:
public struct LAError { public init(_nsError: NSError) public static var _nsErrorDomain: String { get } public enum Code : Int { case authenticationFailed case userCancel // ... @available(iOS, introduced: 8.0, deprecated: 11.0, message: "use LAErrorBiometryNotAvailable") case touchIDNotAvailable @available(iOS, introduced: 8.0, deprecated: 11.0, message: "use LAErrorBiometryNotEnrolled") case touchIDNotEnrolled @available(iOS, introduced: 9.0, deprecated: 11.0, message: "use LAErrorBiometryLockout") case touchIDLockout // ... @available(iOS 11.0, *) public static var biometryNotAvailable: LAError.Code { get } @available(iOS 11.0, *) public static var biometryNotEnrolled: LAError.Code { get } @available(iOS 11.0, *) public static var biometryLockout: LAError.Code { get } // ... } // ...}
And this seems to be the cause for the deprecation warnings, andalso for the problem reported on the swift-users mailing list
that it is impossible to write an exhaustive and warning-freeswitch statement for LAError
.
To prove my conjecture, I have reproduced the problem with a customenumeration: Add the following definition to the bridging headerfile of an macOS 10.13 or iOS 11 project:
#import <Foundation/Foundation.h>typedef NS_ENUM(NSInteger, MyEnum){ MyEnumA = 1, MyEnumB = 2, MyEnumC NS_ENUM_DEPRECATED(10_10, 10_13, 8_0, 11_0, "use MyEnumNewC") = 3, MyEnumNewC NS_ENUM_AVAILABLE(10_13, 11_0) = 3,};
This is imported to Swift as
public enum MyEnum : Int { case A case B @available(OSX, introduced: 10_10, deprecated: 10_13, message: "use MyEnumNewC") case C @available(OSX 10_13, *) public static var newC: MyEnum { get } }
with 3 cases for the first (distinct) enum values, and a staticproperty for the duplicate value.
And indeed, any use of MyEnum
triggers a deprecation warning:
// main.swift:print(MyEnum.A) // Or: let _: MyEnum? = nil// Build log:// <unknown>:0: warning: 'C' was deprecated in OS X 10.13: use MyEnumNewC
In addition, it is not possible to use the new enum value in aswitch statement:
func foo(err: MyEnum) { switch err { case .A: print("A") case .B: print("B") case .newC: print("C") }}// Build log:// main.swift:12:9: error: switch must be exhaustive// <unknown>:0: warning: 'C' was deprecated in OS X 10.13: use MyEnumNewC
even if the compiler (apparently) knows that these cases are exhaustive:
func foo(err: MyEnum) { switch err { // Switch must be exhaustive case .A: print("A") case .B: print("B") case .newC: print("C") default: print("default") }}// Build log:// <unknown>:0: warning: 'C' was deprecated in OS X 10.13: use MyEnumNewC// main.swift:19:9: warning: default will never be executed
This looks like a compiler bug to me.
Yes, these are new warnings which are present as Apple moves to iOS 11 and FaceID. Most likely, you are checking to see if the biometric hardware is not locked out, has enrolled fingerprints, and the device has the supporting hardware.
Here an example set up:
import LocalAuthentication...var authContext = LAContext()var biometricsError: NSError?authContext?.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &biometricsError)
Up to iOS 10, one would run checks like this:
if biometricsError?.code == LAError.touchIDNotAvailable.rawValue { // No hardware}if biometricsError?.code == LAError.touchIDNotEnrolled.rawValue { // No fingerprints}if biometricsError?.code == LAError.touchIDLockout.rawValue { // Locked out}
Note: iOS 11 introduced a slight variant of the above code. Instead of using LAError.touchID
for each error property, they introduced LAError.biometry
. Therefore you would have: biometryNotAvailable
, biometryNotEnrolled
, and biometryLockout
.
Apple seems to prefer this approach, instead:
if biometricsError?.code == Int(kLAErrorBiometryNotAvailable) { // No hardware}if biometricsError?.code == Int(kLAErrorBiometryNotEnrolled) { // No fingerprints}if biometricsError?.code == Int(kLAErrorBiometryLockout) { // Locked out}
This method gets rid of Xcode's warnings.
As has been noted, this is a bug in the compiler. The Swift team are aware and you might want to go and vote for the bug. At the same time, add a watch on it so that you can remove the following workaround when it has been fixed.
What you need to do in order to not get the warnings is: do not mention LAError
. Think of LAError
as Voldemort.
Instead, use Objective-C style error checking. All Error
enums map to an NSError
, which are built up from a domain and a code. The constants to compare these with are also exported to Swift. They can be named without warnings. So your code might look a little (hopefully, very little) like this.
let context = LAContext()let text = "Authenticate, please!"context.evaluatePolicy(.deviceOwnerAuthentication, localizedReason: text) { (success, error) in if success { print("🎉") } else { guard let error = error else { return print("Should not happen according to the docs!") } let nsError = error as NSError switch nsError.domain { case kLAErrorDomain: switch nsError.code { case Int(kLAErrorUserCancel): print("User cancelled.") case Int(kLAErrorBiometryLockout): print("Biometry lockout.") default: print("Unhandled error.") } default: print("Unhandled error domain. Probably will not happen.") } }}