How to convert newline into <br/> with XSLT? [duplicate]
This transformation:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:template match="t"> <p> <xsl:apply-templates/> </p> </xsl:template> <xsl:template match="text()" name="insertBreaks"> <xsl:param name="pText" select="."/> <xsl:choose> <xsl:when test="not(contains($pText, '
'))"> <xsl:copy-of select="$pText"/> </xsl:when> <xsl:otherwise> <xsl:value-of select="substring-before($pText, '
')"/> <br /> <xsl:call-template name="insertBreaks"> <xsl:with-param name="pText" select= "substring-after($pText, '
')"/> </xsl:call-template> </xsl:otherwise> </xsl:choose> </xsl:template></xsl:stylesheet>when applied on this XML document:
<t>Line1Line2Line3</t>produces the wanted, correct result:
<p>Line1<br />Line2<br />Line3<br /></p>