How to get all the info in XML into dictionary with Python

You can use untangle library in python. untangle.parse() converts an XML document into a Python object

This takes an xml file as input and returns a python object which represents that xml document.

Lets take following xml file as an example and name it as test_xml.xml

<A> <B>  <C>"blah1"</C>  <C>"blah2"</C> </B> <B>  <C>"blah3"</C>  <C>"blah4"</C> </B></A>  

Now lets convert the above xml file into a python object to access the elements of xml file

>>>import untangle>>>input_file = "/home/tests/test_xml.xml" #Full path to your xml file>>>obj = untangle.parse(input_file)>>>obj.A.B[0].C[0].cdatau'"blah1"'>>> obj.A.B[0].C[1].cdatau'"blah2"'>>> obj.A.B[1].C[0].cdatau'"blah3"'>>> obj.A.B[1].C[1].cdatau'"blah4"'

I usually use the lxml.objectify library for quick XML parsing.

With your XML string, you can do:

from lxml import objectifyroot = objectify.fromstring(xml_string)

And then get individual elements using a dictionary interface:

value = root["A"][0]["B"][0]["C"][0]

Or, if you prefer:

value = root.A[0].B[0].C[0]

I usually parse XML using the ElementTree module on the standard library. It does not give you a dictionary, you get a much more useful DOM structure which allows you to iterate over each element for children.

from xml.etree import ElementTree as ETxml = ET.parse("<path-to-xml-file")root_element = xml.getroot()for child in root_element:   ...

If there is specific need to parse it to a dictionary, instead of getting the information you need from a DOM tree, a recursive function to build one from the root node would be something like:

def xml_dict(node, path="", dic =None):    if dic == None:        dic = {}    name_prefix = path + ("." if path else "") + node.tag    numbers = set()    for similar_name in dic.keys():        if similar_name.startswith(name_prefix):            numbers.add(int (similar_name[len(name_prefix):].split(".")[0] ) )    if not numbers:        numbers.add(0)    index = max(numbers) + 1    name = name_prefix + str(index)    dic[name] = node.text + "<...>".join(childnode.tail                                         if childnode.tail is not None else                                         "" for childnode in node)    for childnode in node:        xml_dict(childnode, name, dic)    return dic

For the XML you list above this yields this dictionary:

{'A1': '\n \n <...>\n', 'A1.B1': '\n  \n  <...>\n ', 'A1.B1.C1': '"blah"', 'A1.B1.C2': '"blah"', 'A1.B2': '\n  \n  <...>\n ', 'A1.B2.C1': '"blah"', 'A1.B2.C2': '"blah"'}

(I find the DOM form more useful)