POST XML file using cURL command line POST XML file using cURL command line xml xml

POST XML file using cURL command line


If that question is connected to your other Hudson questions use the command they provide. This way with XML from the command line:

$ curl -X POST -d '<run>...</run>' \http://user:pass@myhost:myport/path/of/url

You need to change it a little bit to read from a file:

 $ curl -X POST -d @myfilename http://user:pass@myhost:myport/path/of/url

Read the manpage. following an abstract for -d Parameter.

-d/--data

(HTTP) Sends the specified data in a POST request to the HTTP server, in the same way that a browser does when a user has filled in an HTML form and presses the submit button. This will cause curl to pass the data to the server using the content-type application/x-www-form-urlencoded. Compare to -F/--form.

-d/--data is the same as --data-ascii. To post data purely binary, you should instead use the --data-binary option. To URL-encode the value of a form field you may use --data-urlencode.

If any of these options is used more than once on the same command line, the data pieces specified will be merged together with a separating &-symbol. Thus, using '-d name=daniel -d skill=lousy' would generate a post chunk that looks like 'name=daniel&skill=lousy'.

If you start the data with the letter @, the rest should be a file name to read the data from, or - if you want curl to read the data from stdin. The contents of the file must already be URL-encoded. Multiple files can also be specified. Posting data from a file named 'foobar' would thus be done with --data @foobar.


From the manpage, I believe these are the droids you are looking for:

-F/--form <name=content>

(HTTP) This lets curl emulate a filled-in form in which a user has pressed the submit button. This causes curl to POST data using the Content-Type multipart/form-data according to RFC2388. This enables uploading of binary files etc. To force the 'content' part to be a file, prefix the file name with an @ sign.

Example, to send your password file to the server, where 'password' is the name of the form-field to which /etc/passwd will be the input:

curl -F password=@/etc/passwd www.mypasswords.com

So in your case, this would be something like
curl -F file=@/some/file/on/your/local/disk http://localhost:8080


You can using option --data with file.

Write xml content to a file named is soap_get.xml and using curl command to send request:

curl -X POST --header "Content-Type:text/xml;charset=UTF-8" --data @soap_get.xml your_url