Simplest way to do basic xml parsing from unix command line

The following linux command uses XPath to access specified values within the XML file

for xml in `find . -name "*.xml"`do  echo $xml `xmllint --xpath "/param-value/value/text()" $xml`| awk 'NF>1'done

Example output for matching XML files:

./test1.xml asdf./test4.xml 1234

I worked out a couple of solutions using basic perl/awk functionality (basically a poor man's parsing of the tags). If you see any improvements using only basic perl/awk functionality, let me know. I avoided dealing with multiline regular expressions by setting a flag with I see a particular tag. Kind of clumsy but it works.

perl:

perl -ne '$h = 1 if m/Host/; $r = 1 if m/Role/; if ($h && m/<value>/) { $h = 0; print "hosts: ", $_ =~ /<value>(.*)</, "\n"}; if ($r && m/<value>/) { $r = 0; print "\nrole: ", $_ =~ /<value>(.*)</, "\n" }'

awk:

awk '/Host/ {h = 1} /Role/ {r = 1} h && /<value>/ {h = 0; match($0, "<value>(.*)<", a); print "hosts: " a[1]} r && /<value>/ {r = 0; match($0, "<value>(.*)<", a); print "\nrole: " a[1]}'

$ xmlstarlet ed -u /param-value/name -v Roles -u /param-value/value -v asdf data.xml<?xml version="1.0"?><param-value>  <name>Roles</name>  <description>some description</description>  <value>asdf</value></param-value>