How to access command line arguments of the caller inside a function?

How to access command line arguments of the caller inside a function?

bash command-line-arguments argv

bash

Strange behavior of argv when passing string containing "!!!!"

c bash quotes argv

bash

How to change argv0 in bash so command shows up with different name in ps?

bash argv ps

bash

BASH scripting: n-th parameter of $@ when the index is a variable?

bash shell argv

bash